0. you have to throw a xmlrpclib.Fault instance in the called method at the zope side this is then correctly thrown as exception at the xmlrpclib client: raise xmlrpclib.Fault(<errorcode>,<errormessage>) 1. you have to modify the standard_error_message as: <dtml-return error_value> then you can catch the fault at the client (assume 'server' is the connection) : try: server.test() except xmlrpclib.Fault,f: print 'fault:',f hope that helps phil Tobias Oberstein wrote:

lets say i call some method of an zope object via xml-rpc and

* give wrong parameters or * throw an exception within the method

for example. then the result served by zope will be a html page describing the error, not an XML-RPC fault response like the spec describes it.

how can i change this behaviour ?

greets, tobias

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