import re
import string

_stripstart = re.compile('^(\s*[\n\r])+')

def wrap(text,width=70):

    # Strip trailing whitespace and expand tabs for proper counting.
    text = string.expandtabs(string.rstrip(text))

    # Strip all leading blank lines
    text = _stripstart.sub('',text,1)

    # Our output
    out = ''

    # When I grow up, I want to be a Perl programmer
    for m in re.findall(
	'(?mx) [^\n]{1,%d} (?=\s) [ ]* [\n]?  | [^\n]{1,%d} [\n]?  | \n' 
	    % (width,width),text):
	
	out = out + string.rstrip(m) + '\n' 

    return string.rstrip(out)


if __name__ == '__main__':
    a = '''

    

    this is a long string that hopefully will be wrapped correctly so lets see how it goes. Note that this line is indented.
Blah  blah blah blah
This line terminates on exactly the sixtyninth character so toto test
This line terminates on exactly the seventy-eth character      to test
This line terminates on exactly the seventyfirst character to test ifit


blah two blank lines above

  70 chars on the next line
1234567890123456789012345678901234567890123456789012345678901234567890

80 chars on the next line
12345678901234567890123456789012345678901234567890123456789012345678901234567890

160chars on the next line
1234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890

   '''

    a = wrap(a)

    print a