in the method (probably a python script) dealing with the upload use the following
I patched it from several of my methods. It is not tested but it should give you the idea
 
 
Robert
 
Call this function as a the action of a file upload form.
If it is in a python script just leave out the def part, and give the script the
parameter file.
    def manage_addMyFile ( self, file ) :
        """ add file """
        import os
        if hasattr(file,'filename'):
            filename=file.filename
            title=filename
            id=filename[max(string.rfind(filename, '/'),
                            string.rfind(filename, '\\'),
                            string.rfind(filename, ':'),
                            )+1:]
 
        if(file):
            if(os.path.splitext(filename)[1] in ['.jpg', '.gif']):
                self.manage_addImage(id, title, file)
            if other extention ....
----- Original Message -----
From: Mark Spencer
To: zope@zope.org
Sent: Monday, March 25, 2002 2:46 AM
Subject: [Zope] How to upload files and create file objects from DTML page?

I want to have a normal DTML page for users that allows them to upload and download files (without needing to use the management interface). The downloading and display of files is fine, but I cant figure out the zope/python code to create a new file object and store an uploaded file. The files could be upto ~60MB in size, and can be zip or doc files etc. Has anyone seen suitable sample code for this?