[Zope-dev] Extrenal method unable to run the os.popen() or
os.system() commands
Wichert Akkerman
wichert at wiggy.net
Wed Feb 14 04:44:31 EST 2007
Previously Ridzwan Aminuddin wrote:
> Hi!
>
> Thanks for your reply.
>
> I heeded your advice and tried fooling around with the stderr. Apparently even if i set the classpath through my execution statement i.e :
>
> command = "java -jar -classpath "/var/lib/zope2.8/instance/plone-site/Extensions/ test.jar"
> os.system(command)
>
> it doesn't seem to work. Because even though i have denoted the path to the jar file, this python external method requires me to be in the atual working directory in order o sucessfully run this command.
>
> What i tried was to write a shell script instead
>
> #!/bin/bash
> # My shell script
> path='/var/lib/zope2.8/instance/plone-site/Extensions'
> cd $path
> java -jar test.jar
>
>
> this shell script is executed by my external method :
>
> command = "home/ewan/myScript"
> os.system(command)
>
> This works perfectly. So now i know it has to do with the physical working directory i am in. Simply setting the classpath doesn't work or giving the absolute path to the jar file doesn't work either.
>
> i.e :
>
> command = "java -jar /var/lib/zope2.8/instance/plone-site/Extensions/test.jar"
> os.system(command)
>
> Anyone knows why this is so? and is there any way around this? I find
> it inefficient that i have my DTML calling My Python calling a Shell
> Script that runs an executable. Such a long chain!
That is due to something in your java setup or java application, not
something in Zope. So we can't help you with that.
Wichert.
--
Wichert Akkerman <wichert at wiggy.net> It is simple to make things.
http://www.wiggy.net/ It is hard to make things simple.
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