[Zope] Re: cannot start Zope 2.0.0 alpha 2

[J Kinsley]

I remember getting a similar error awhile back on a CVS version of
Zope.  The reason was that I forgot to set the DNS_IP in z2.py.

Regards,
Jarrod Kinsley

> On Mon, 14 Jun 1999 19:07:16 -0400,
> Jim Fulton <jim@digicool.com> said:
> 
> Jim>   http://www.zope.org/Download/Releases/Zope-2.0.0a2
> 
> Something seems wrong here. I can get 2.0a1 to start, but not 
> 2.0a2, using the exact same procedure.
> 
>    tar xvzf Zope-2.0.0a1-src.tgz 
>    cd Zope-2.0.0a1-src
>    python wo_pcgi.py 
>    chown -R nobody var/
>    chgrp -R nobody var/
>    python z2.py 
>
> (now can browse Zope on port 9673)
> (kill Zope)
> 
>    tar xvzf Zope-2.0.0a2-src.tgz 
>    history
>    cd Zope-2.0.0a2-src
>    python wo_pcgi.py 
>    chown -R nobody var/
>    chgrp -R nobody var/
>    python z2.py 
> 
> (now cannot browse Zope on port 9673)
> 
> Unhandled exception in thread:
> Traceback (innermost last):
>   File
> "/usr/share/Zope-2.0.0a2-src/ZServer/PubCore/ZServerPublisher.py",
> line 97, in __init__
>    response._finish()
>   File "/usr/share/Zope-2.0.0a2-src/ZServer/HTTPResponse.py", line
> 214, in _finish
>     self.stdout.close()
>   File "/usr/share/Zope-2.0.0a2-src/ZServer/HTTPResponse.py", line
> 249, in close
>     Wakeup()
>   File "/usr/share/Zope-2.0.0a2-src/ZServer/medusa/select_trigger.py",
> line 80, in pull_trigger
>     self.trigger.sendto (msg, self.addr)
> socket.error: (13, 'Permission denied')
> 
> My system:
> 
> Linux 2.2
> Python 1.5.2
>