[Zope] Socket Error (newbie)
Petru Paler
ppetru@coltronix.com
Thu, 13 Apr 2000 23:54:38 +0300
On Thu, Apr 13, 2000 at 03:48:11PM -0500, jessica lee tishmack wrote:
> > > socket.error: (98, 'Address already in use')
> > >
> > > I tried doing netstat -a and didn't see 98 or tacnews there (saw this in
> > > an archived e-mail...but wasn't if that's what I should look for).
> >
> > 98 is the socket error code, not the port being already in use.
>
> Oh, okay. Hmm...maybe the solution to my problem can be better solved
> with more info then...here is the entire message I get when I run
> ./start....this message will just keep appearing over and over again on my
> screen.....til I manually end the program.
>
> Traceback (innermost last):
> File "/home/jessi/Zope-2.1.6-src/z2.py", line 493, in ?
> logger_object=lg)
> File "/home/jessi/Zope-2.1.6-src/ZServer/medusa/http_server.py", line
> 552, in __init__
> self.bind ((ip, port))
> File "/home/jessi/Zope-2.1.6-src/ZServer/medusa/asyncore.py", line 205,
> in bind
> return self.socket.bind (addr)
> socket.error: (98, 'Address already in use')
What does
fuser -v 80/tcp 8080/tcp
say ?
-Petru