[Zope] Socket Error (newbie)

Petru Paler ppetru@coltronix.com
Thu, 13 Apr 2000 23:54:38 +0300


On Thu, Apr 13, 2000 at 03:48:11PM -0500, jessica lee tishmack wrote:
> > > socket.error: (98, 'Address already in use') 
> > > 
> > > I tried doing netstat -a and didn't see 98 or tacnews there (saw this in
> > > an archived e-mail...but wasn't if that's what I should look for).
> > 
> >    98 is the socket error code, not the port being already in use.
> 
> Oh, okay.  Hmm...maybe the solution to my problem can be better solved
> with more info then...here is the entire message I get when I run
> ./start....this message will just keep appearing over and over again on my
> screen.....til I manually end the program.
> 
> Traceback (innermost last):
>   File "/home/jessi/Zope-2.1.6-src/z2.py", line 493, in ?
>     logger_object=lg)
>   File "/home/jessi/Zope-2.1.6-src/ZServer/medusa/http_server.py", line
> 552, in __init__
>     self.bind ((ip, port))
>   File "/home/jessi/Zope-2.1.6-src/ZServer/medusa/asyncore.py", line 205,
> in bind
>     return self.socket.bind (addr)
> socket.error: (98, 'Address already in use')   

   What does

fuser -v 80/tcp 8080/tcp

   say ?

-Petru