[Zope] Simple Count Method (even simpler ;)
Jim Sanford
jsanford@atinucleus.com
Sun, 12 Mar 2000 13:38:07 -0600
select count(*) as classcount form whowhat where whatever=whatever
----- Original Message -----
From: Tino Wildenhain <tino@wildenhain.de>
To: <zope@zope.org>
Sent: Saturday, March 11, 2000 12:08 PM
Subject: Re: [Zope] Simple Count Method (even simpler ;)
Curtis Maloney wrote:
>
> On Fri, 10 Mar 2000, Joseph A. Archer wrote:
> > To all Zopist,
> >
> > (I am new to the list, and yes I am going through the archives for the
> > answer, but haven't found it yet.)
> >
> > I have a simple two field table in MySQL, "whowhat", that pulls a user id
> > from one table, and a class code from another. (It tells you "who" has
> > "what" classes)
> >
> > I , being somewhat new to python & Zope, am having the darndest time trying
> > to do a simple external method to do a count of how many times the class
> > "so-and-so" is in the table. (That way, I know how many people have
> > signed-up, and how close I am to the class max.) I have tried different
> > searches. I have an SQL Method that does:
> >
> > select * from whowhat
> >
> > And I also have one that does:
> >
> > ...
> > sselect * from whatwhat where classcode = <dtml-sqlvar class_name type=nb>
> >
> > I've been trying to create an External Method, but I just can't seem to get
> > it to work. (yes, in the Extentions directory)
> >
> > I need to try to stay away from doing a "select count(classcode)..." in an
> > SQL Method if I can.
> >
> > Any help to this tormented soul would be greatly appreciated.
> >
>
> Greetings,
>
> In my experience, to count the size of an array in ZOPE does not require an
> external method, simply "_.len(sqlQuery())". I use this myself in a few places.
>
> I won't try to guess your reasons for not getting sql to count, but surely it
> would be by far the simplest way?
How about
<dtml-in sqlQuery>
<dtml-var sequence-lenght>
</dtml-in>
?
There also some more statistics over the columns. Please refer to
the manual for more.
Best regards
Tino Wildenhain
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