[Zope] a problem with 'start' command

[Gabriela Arevalo]

Phil,

thanks for your suggestion, i understood it

> If you are in the Zope directory, since most uni(x)es don't have the current
> directory in the path, you need to start zope with './start'.

but now when i execute the command i have the following message:

-----------------------------------------------------------------------------

Traceback (innermost last):
  File "/home/pecos/zope/Zope-2.2.2-solaris-2.6-sparc/z2.py", line 537, in
?
    zdaemon.run(sys.argv, os.path.join(CLIENT_HOME, Zpid))
  File
"/home/pecos/zope/Zope-2.2.2-solaris-2.6-sparc/lib/python/zdaemon.py",
line 204, in run
    pf.close()
IOError: [Errno 49] Disc quota exceeded
aurora:~/zope/Zope-2.2.2-solaris-2.6-sparc.24 % ------
2000-10-23T15:18:55 PROBLEM(100) ZServer Computing default hostname
------
2000-10-23T15:18:55 INFO(0) ZServer Medusa (V1.16.4.3) started at Mon Oct
23 17:18:55 2000
        Hostname: aurora
        Port:8080

------
2000-10-23T15:18:55 INFO(0) ZServer FTP server started at Mon Oct 23
17:18:55 2000
        Authorizer:None
        Hostname: aurora
        Port: 8021
------
2000-10-23T15:18:55 ERROR(200) ZServer Cannot write PID file.
------
2000-10-23T15:18:55 INFO(0) ZServer PCGI Server started at Mon Oct 23
17:18:55 2000
        Unix socket:
/home/pecos/zope/Zope-2.2.2-solaris-2.6-sparc/var/pcgi.soc
------
2000-10-23T15:18:55 INFO(0) ZServer Monitor Server (V1.8.4.1) started on
port 8099
Traceback (innermost last):
  File "/home/pecos/zope/Zope-2.2.2-solaris-2.6-sparc/z2.py", line 715, in
?
    pf.close()
IOError: [Errno 49] Disc quota exceeded

------------------------------------------------------------------------------

what does this message mean ? what can i do ?

in fact, my problem is when i tried to execute
"localhost":8080/pecos/ where i have the information i need, there seems
to have problems, because the connection is not possible.
first thing i thought is just to try to start the server again, but i can
not.

thanks for any help

have a nice evening.

Gaby