[Zope] need help - python problem
Kam Nejad
knejad@codeit.com
Mon, 26 Feb 2001 17:48:04 -0800
I am writing a program that would allow me to send email with
attachments.
The code works, however instead of attachments I get the actual contects
of the attachments. If anybody knows how to solve this problem in python
I would be grateful for your help.
#!/bin/usr/env python
import smtplib
import pdb
import MimeWriter
import quopri, base64
import StringIO
import sys
def shoot(msgFrom, msgTo, msgSubj, msgBody):
mailSvr = ""
server = smtplib.SMTP(mailSvr)
msg1 = "From: %s\nTo: %s\nSubject: %s\n\n%s" % (msgFrom, msgTo,
msgSubj, msgBody)
retVal = server.sendmail(from_addr=msgFrom, to_addrs=msgTo, msg=msg1)
server.quit()
return (retVal)
def main():
inputFile = open("readit.dat", "r")
attachment = open("result.jpg", "rb")
mimefile = open("output.msg", "w") #create output file object
needed by quopri.encode()
mimemsg = MimeWriter.MimeWriter(sys.stdout)
mimemsg.addheader("Mime-Version", "1.0")
mimemsg.startmultipartbody("mixed")
msgpart = mimemsg.nextpart()
msgpart.addheader("Content-Transfer-Encoding", "quoted-printable")
msgpart.startbody("text/plain")
quopri.encode(inputFile, mimefile, 0)
msgpart = mimemsg.nextpart()
msgpart.addheader("Content-Transfer-Encoding", "base64")
msgpart.startbody("image/jpeg")
quopri.encode(attachment, mimefile, 0)
mimemsg.lastpart()
mimefile.close()
messageFile = open("output.msg", "r")
messageBody = messageFile.read()
shoot("knejad@codeit.com", "knejad@codeit.com", "test", messageBody)
inputFile.close()
attachment.close()
messageFile.close()
#pdb.set_trace()
main()
#pdb.set_trace()