[Zope] string module

[Sebal]

>On 13 Jun 2001 07:47:13 -0700, Sebal wrote: 
>> I have a method what from a "MULTIPART FORM" put a file named
'myFile.pdf' 
>> in a directory. 
>> And after i want the methood to create a Zclass instance[PDFclass] whith 
>> id=myFile. 
>> 
>> I tried  with split, join, and translate method of string module, and I 
>> can't get a valid id with split and join ; and with translate if 'myFile'
is 
>> 'mypdf' (so the file is 'mypdf.pdf') I'll get 'my' as id for my PDFclass 
>> instance. 
>
>
>Split on the '.' not on 'pdf'. 
>
>Example from the interpreter: 
>	>>> foo="mypdf.pdf" 
> 	>>> id,extension = string.split(foo,'.') 
>	>>> print id 
>       mypdf 
>
>Bill 

This doesn't work:
1>>>mydtml_method.html:
<dtml-call "REQUEST.set('filename' , 'test.pdf')" >
<dtml-call "REQUEST.set('file_id' , _.string.split(filename,'.'))" >
<dtml-var file_id>

with view I get ['test','pdf']

2>>>mydtml_method.html:
<dtml-call "REQUEST.set('filename' , 'test.pdf')" >
<dtml-call "REQUEST.set('file_id' , _.string.split(filename,'.pdf'))" >
<dtml-var file_id>

with view I get ['test','']

This make a invalide id for my PDFclass instance.
I don't know how to separate the 2 arguments of file_id.

Thanx

    ()                      	
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  (____)   zazen rules ... Sbaline





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