[Zope] FileUpload and Python Script

[Tom Deprez]

Urgh,

thanks, looking at your example, I saw that what I did would normally work.
I made a mistake, ie before the user can insert it in the database, I show
it as a preview.
>From the preview I call the python script... but that's where it was
wrong... I transformed it to a string.

I changed the code and now it works. pfew, I think without your message I
would have looked over the error everytime.

Tom.
----- Original Message -----
From: "Flynt" <rhess@bic.ch>
To: "Tom Deprez" <tom.deprez@village.uunet.be>
Cc: <zope@zope.org>
Sent: Sunday, June 17, 2001 6:01 PM
Subject: Re: [Zope] FileUpload and Python Script


> Tom Deprez wrote:
> >
> > Can somebody help me on how I can get the filename of a FileUpload
object in
> > a python script?
> >
> > When using following code in a python script,
> >
> > context.REQUEST['accessory_image'].filename
> >
> > I get always the following error :
> >
> > Error Type: AttributeError
> > Error Value: 'string' object has no attribute 'filename'
> >
> > It's obvious that I doing something wrong, but what?
> >
> > Thanks Tom.
>
> Hi Tom
>
>
> I don't know, what you would like to do, but maybe I might be able to
> help with a simple example: A file gets uploaded via a form and then I
> print the content of the file on the screen. Perhaps this can serve you
> as some kind of starting point.
>
>
> First create a DTML method with id *uploadForm* and content:
>
> <dtml-var standard_html_header>
> <FORM ACTION="uploadFile" METHOD="POST" ENCTYPE="multipart/form-data">
> <INPUT TYPE="file" NAME="file" SIZE="25" VALUE=""><br>
> <INPUT TYPE="SUBMIT" VALUE="Upload">
> <dtml-var standard_html_footer>
>
>
> Then create a python script with id *uploadFile* and content:
>
> try:
> a = context.REQUEST.file.read()
> print a
> return printed
> except KeyError:
> print '''There was a key error:
> The script did not get
> the the field named *file*
> from your HTML form in *REQUEST* !'''
> return printed
>
>
> You do *not* have to set any bindings! Just this content in the script !
> If you click the *Test* tab for the script you will see the error text,
> because you didn't privide a key *file* during this test (as this
> variable comes from the form).
>
>
> Now, call the *uploadForm* method, and you will see the form on your
> screen. Choose a file on your harddisk (preferably a text or HTML file
> for this simple example, otherwise you get a funny screen, because the
> content of the file will get printed) and click the *Upload* button. You
> should see the content of that file on your screen then.
>
>
> If you would like to see, what your *REQUEST* looks like, you can simply
> put this code into your script *uploadFile*, which gets called by
> *uploadForm*:
>
> print context.REQUEST
> return printed
>
>
> HTH
> --- Flynt