[Zope] Extracting a part of a string

[Andreas Jung]

Something like that should work:

import re
reg = re.compile('\(.*\)')
print reg.sub('','some words (another words)')

The regular expression finds all occurences of text between two braces
and replaces then with the empty string.

Andreas


----- Original Message -----
From: sbergmann@weblog.de
To: zope@zope.org
Sent: Friday, June 29, 2001 8:56 AM
Subject: [Zope] Extracting a part of a string



Hello Zopers,

I have the following problem:

I have a string from a database and want to delete a part from the string
and write it back to the database.

An example:

a = ' some words ( another words)'
I want to extract now everything without the brackets themselves anth the
words in the brackets.
That should be the result.

a = 'some words'

How can I do that. With the string-module and "find"  I can get the index
where the brackets begin. But there is no function to get the string from
index 0 to the result  index of "find".

Is there another way to do this?

I´m sure that somebody has a solution for me.


Steffen