[Zope] stupid question

michael angelo ruberto michaelangelo@webmind.com
Tue, 6 Mar 2001 17:47:12 -0500


it seems i was performing some uneccessary steps here. i can just print the
getContentType method. the problem is trying to trap just the object type.
this works:

<ul>
      <dtml-in expr="PARENTS[0].objectValues('File')">
        <li><a href="<dtml-var absolute_url>"><dtml-var id></a> <dtml-var
getContentType></li>
      </dtml-in>
</ul>

so the problem is with this:

              <dtml-if sequence-item.objectValues(['File'])>

i must find another way to trap for File objects during the iteration.

-<mike>-


-----Original Message-----
From: Jonothan Farr [mailto:jfarr@real.com]
Sent: Tuesday, March 06, 2001 5:37 PM
To: michaelangelo@webmind.com
Cc: zope
Subject: Re: [Zope] stupid question


Python doesn't like the "sequence-item.getContentType()" part. Try:
"_['sequence-item'].getContentType()"

--jfarr

----- Original Message -----
From: "michael angelo ruberto" <michaelangelo@webmind.com>
To: <zope@zope.org>
Sent: Tuesday, March 06, 2001 2:26 PM
Subject: [Zope] stupid question


> hi,
>
> why doesn't this work?
>
>
>              <dtml-if sequence-item.objectValues(['File'])>
>              <td bgcolor="#EEEEEE"><dtml-let
> cType="sequence-item.getContentType()"><dtml-var cType></dtml-let></td>
>              <dtml-else>
>              <td bgcolor="#EEEEEE"><dtml-var meta_type></td>
>              </dtml-if>
>
>
> is there some other way to display the content type of a file?
>
> thanks
>
> -<mike>-
>
>
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