[Zope] File Upload via python

[Dieter Maurer]

Jonathan Bryant writes:
 > I've been playing around with Zope for several days and really like it. I'm 
 > amazed at how simple so many things that take alot of effort in php, asp 
 > etc. are amazingly simple in Zope. One of those things is file upload,...
 > ....
 > What I'd like to do is easily grab the filename:
 > 
 > context.manage_addProduct['OFSP'].manage_addFile(item.filename, item_title, 
 > item)
This should work as you write it here.

 > My question is, how do I get the filename or headers? I'm guessing that when 
 > I reference 'item' I'm getting a FileUpload object.
Right!

 > What confuses me is that 
 > I can't reference item.filename or item.headers['Content-Type']. I've also 
 > tried using REQUEST['item'].filename like I've seen in several examples. 
All of these should work!

The access to "headers" may throw an "Unauthorized" exception
because in former Zope versions, a security declaration was missing
(not sure about the current version).

What happens for you: an "Unauthorized" exception, an "AttributeError",
or what?


We always want good problem descriptions.
Such descriptions contain "Error Type", "Error Value"
and usually (at least) the last part of the resulting traceback!


Dieter