[Zope] Re: Sorting objectValues in Python Script
Andreas Tille
tillea@rki.de
Fri, 18 Oct 2002 10:32:56 +0200 (CEST)
On Fri, 18 Oct 2002, Jerome Alet wrote:
> > > list = context.objectValues('ExtFile')
> > > for file in list:
> > > print file.id, file.title
> > > return printed
> >
> > <UNTESTED>
> > list.sort(lambda x,y : cmp(y.getId(), x.getId()))
> > </UNTESTED>
>
> Sorry I think this won't work in a Python Script because IIRC
> lambda is forbidden there.
Hmmm, I have to search my Python intro what lambda is, but it works as
expected:
list = context.objectValues('ExtFile')
list.sort(lambda x,y : cmp(y.getId(), x.getId()))
for file in list:
print file.id, file.title
return printed
is absolutely fine.
> Replace the lambda with a normal function and it should be ok.
Just for the sake of interest: What do you mean with "normal function"?
Many thanks for the very quick answer!!!!
Kind regards
Andreas.