[Zope] Calling a File from an External Method

[Dieter Maurer]

beno wrote at 2003-1-11 16:32 -0400:
 > I'm calling a function with a file name from an external method. I need to 
 > pass a variable to the method, so I have a line like this:
 > 
 > <dtml-var expr="externalMethod('file')">
 > 
 > but the error comes back thus:
 > 
 > IOError: [Errno 2] No such file or directory: 'file'
Apparently, you are using Python's "open" function (or friend).
It resolves relative filenames with respect to the "currend working
directory".
The "current working directory" must not change during Zope
execution. Especially, it can not be dependent on the location
of an "External Method" or DTML object.

I am not sure, what Zope's current working directory is.

  I expect it is the directory where Zope has been started.

  But, there are rumors that this may have been changed
  and the current working directory is now "CLIENT_HOME"
  (per default the "var" subfolder).

Either use absolute path names to your files or find out what
the current working directory is (Python has an function
for thin in the "os" module) and use relative filenames with
respect to this directory.


Dieter