[Zope] How to pass a Z SQL method a variable from a Python Script?

[Ben Avery]

for starters, you should be using <dtml-zsqlvar ...> rather than 
<dtml-var ...>, for security. Then removing the quotes, so your method 
looks like:

insert into name_table
(CName, email, phone)
values
(<dtml-sqlvar CName type="string">, <dtml-sqlvar email type="string">, 
<dtml-sqlvar phone type="string">)

then call using parameter names from the python script:

context.send_to_database(CName=CName, email=email, phone=phone)

does that work?

HTH

Ben Avery

p.s. cute kitten


Sage Mo wrote:
> This is probably a very basic question, but it's been stopping me for 
> hours (very frustrating).
>  
> I have a Python script that's trying to pass variables into a Z SQL 
> method. In the Python script I wrote:
>  
> container.send_to_database(CName, email, phone)
>  
> where send_to_database is the Z SQL Method.
>  
> send_to_database looks like this:
>  
> 
> Z SQL Method *Z SQL Method at  / 
> <http://www.heiropure.com/manage_workspace>send_to_database*
> Help! 
> <http://www.heiropure.com/HelpSys?help_url=/Control_Panel/Products/ZSQLMethods/Help/Z-SQL-Method_Edit.stx> 
> 
> 
> Title
> Connection Id
> Arguments
>  
> Yet when I run the Python script, I get
>  
> 
> 
>     Zope Error
> 
> Zope has encountered an error while publishing this resource.
> 
> *Error Type: KeyError*
> *Error Value: CName*
> 
> Am I passing the variables in the wrong way from the Python Script? Is 
> there something wrong with the Z SQL method? In the Python script the 
> variables CName, email, phone are well defined. Someone, anyone HELP! so 
> I can actually do something besides look hopelessly at this error 
> message for days on end.
> 
>