[Zope] Newbie Q: How do I cal ZPT objects from a python script
object?
Joe Block
jpb at apesseekingknowledge.net
Mon Dec 6 14:36:45 EST 2004
I'm running Zope 2.6.3 on Mac OS 10.3.6 (installed via fink).
I'm trying to call a very simple page template from inside a python
script object to display a message (in this case, the results of a
database insert).
Here's my results page template:
<html>
<head>
<title tal:content="template/title">The title</title>
<style type="text/css">
@import "/octavo/css/style.css";
</style>
</head>
<body>
<p><span tal:replace="request/msg">msg</span></p>
<div align="center">
<p>Logged in as <span tal:content="user/getUserName">User</span></p>
</div>
</body>
</html>
If I type the template's URL into a browser
(<http://athena.local.:8080/octavo/trackart/results?
msg=Foo%20bar%20baz>), it displays Foo bar baz as expected. I just
can't call the template from within my python script, when I try I get
the following error message
Zope Error
Zope has encountered an error while publishing this resource.
Error Type: KeyError
Error Value: msg
I'm calling it from within the script object like so:
msg = '%s added to client %s' % (job_id, clientname)
return container.results(msg = msg)
The script is in the same folder as the results template.
I know there has to be something simple I'm missing, but I've banged my
head against the wall for a while and haven't made any progress.
jpb
--
Joe Block <jpb at ApesSeekingKnowledge.net>
Computer Science is about lofty design goals and algorithmic
optimization. System Administration is about cleaning up the resulting
mess.
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