[Zope] Zope.app() error

Jens Vagelpohl jens at dataflake.org
Thu Jun 24 11:10:06 EDT 2004


> [root at server2 local]# python2.3
>>>> import ZODB, Zope
>>>> app = Zope.app()
>
> And get an error.  This is the first time I'm doing this with 2.7, is
> this the problem?  Any ideas on how to resolve this?
>

With Zope 2.7 you should use the zopectl script that comes with it 
instead of manually importing zope. Running "zopectl debug" 
automatically does what you are trying to do.

jens



More information about the Zope mailing list