[Zope] Zope.app() error
Jens Vagelpohl
jens at dataflake.org
Thu Jun 24 11:10:06 EDT 2004
> [root at server2 local]# python2.3
>>>> import ZODB, Zope
>>>> app = Zope.app()
>
> And get an error. This is the first time I'm doing this with 2.7, is
> this the problem? Any ideas on how to resolve this?
>
With Zope 2.7 you should use the zopectl script that comes with it
instead of manually importing zope. Running "zopectl debug"
automatically does what you are trying to do.
jens
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