[Zope] Re: tal expression

[Garito]

Duncan Booth wrote:

>Garito wrote:
>
>  
>
>>>Hi
>>>will these be possible?
>>>
>>><tal:b tal:define='dictionary python: {"value1": ["one", "two", 
>>>"three"], "value2": "two", "value3": "three"}'>
>>>   <tal:b tal:replace='python: dictionary["value1"][5] | "Value not 
>>>available"' />
>>></tal:b>
>>>
>>>Obviously these is an incorrect tal expression (the replace one) but 
>>>there are any way to create an expression like these and correct?
>>>
>>>Thank you!!!
>>>
>>>      
>>>
>>Now I have a correct expression (thanks to Chema Cortés from spanish 
>>zope list). This is the expression:
>>
>>(len(dictionary['value1'])>6 and dictionary['value1'][5]) or 'Value
>>not available' 
>>
>>Thanks for all your help!!!
>>    
>>
>
>An alternative that should work (although it is untested):
>
><tal:b replace="dictionary/value1/5|string:Value not available" />
>
>
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Sorry but your solution doesn't work (Value not available in all cases)
I think these work with an array like:

{"value1": {"1": "One", "2": "Two", "5": "Five"}}

But thanks!