[Zope] zopectl debug question

[Jean Jordaan]

Hi all

Does anyone know how I can "be someone" besides Anonymous when
debugging Zope? This works:

"""
In [80]: 
Zope.debug('/fab/materials/invokeFactory?type_name=Material&id=test2', 
u='user:secret', )

____________________________________________________________

Status: 302 Moved Temporarily
X-Powered-By: Zope (www.zope.org), Python (www.python.org)
Content-Length: 5
Content-Type: text/plain
Location: http://localhost/Zope/fab/materials/test2/base_edit

test2
"""

But I want to do stuff like:

"""
In [83]: at = app.fab.materials.invokeFactory('Material', 'test3')
[...]
Unauthorized: Your user account is defined outside the context of the 
object being accessed.  Access to 'addMaterial' of 
(__FactoryDispatcher__ instance at 41c540d0) denied. Your user account, 
jean, exists at /acl_users. Access requires 
Fabrinox__Add_Materials_Permission, granted to the following roles: 
['Manager'].
"""

Hey! I'm not Anonymous! :)  It still doesn't work though. Without
that Zope.debug call I would've got

"""
Unauthorized: Your user account does not have the required permission. 
Access to 'addMaterial' of (__FactoryDispatcher__ instance at 419f0a00) 
denied. Your user account, Anonymous User, exists at (unknown). Access 
requires Fabrinox__Add_Materials_Permission, granted to the following 
roles: ['Manager']. Your roles in this context are ['Anonymous'].
"""

Hmmm, now does anyone know how I can get hold of that user object
so that I can try and make it __of__(portal)?

-- 
Jean Jordaan
http://www.upfrontsystems.co.za