[Zope] PIL: can't call same method twice

[Chris]

Hi David,

this is not the problem (tried it before).

The code
foo  = container.resize(context.REQUEST.image, size=size) # works nicely
foo  = container.resize(context.REQUEST.image, size=size) # 2nd time ->error
does what you suggest. But it raises the same error.

I looked at the request to see whether image is altered during the 
resize (but why should it be altert at all?): before and after resize 
the request has
image	<ZPublisher.HTTPRequest.FileUpload instance at 0x9668e2c>
as expected.

It lookt more like a bug (?!?) in the PIL-code. So I looked into the 
open method of PIL.Image.py (PIL 1.1.4) to no avail. With my limited 
knowedge I could not see anything obvious. The open() method opens the 
file "read-only" and tryes to identify the file by reading some header 
information of the file instance. This is failing however. I guess the 
prefix is not identified correctly. To do this, open() reads the first 
16 characters ot the file. Since I don't know much about the header 
informations of images (tryed jpg and gif) I can not tell whether they 
are correct.

So I still have no clue :-(

Regards Chris


David Hassalevris wrote:
> 
> Maybe move this line
> 
> image=context.REQUEST.image # passed from a html-form
> 
> inside your for loop.  Maybe image is being changed iteratively.
> eg,
> 
> for i in range(0,x):
>    image=context.REQUEST.image # passed from a html-form
>    foo = context.resize(image, size=size)
> 
> Just a guess,
> David
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