For Python 2.1 the call must be: s.connect( (host,int(port) ) Andreas ----- Original Message ----- From: "Alex Kelly" <KellyA@gw.franklin.edu> To: <zope-dev@zope.org> Sent: Mittwoch, 8. August 2001 13:42 Subject: [Zope-dev] 2.3.3 to 2.4 with zctl.py I have ZEO running with Zope 2.3.3. I followed the instructions at http://www.zope.org/Members/dshaw/AdvancedSiteSetup to set this up. I wanted to upgrade Zope to 2.4. My thinking was that I should be able to replace my Zope_software_installation directory with the contents of 2.4 and restart Zope. I also wanted to use the zctl.py script that is described in the howto listed above, however when I run that script with 2.4, I get: # ./zctl.py start Traceback (most recent call last): File "./zctl.py", line 332, in ? _dispatch() File "./zctl.py", line 329, in _dispatch globals()[action](args) File "./zctl.py", line 132, in start start_zeo(zeo_args) File "./zctl.py", line 145, in start_zeo if host == 'localhost' and not _check_for_service(host, port): File "./zctl.py", line 301, in _check_for_service s.connect(host, int(port)) TypeError: connect() takes exactly 1 argument (2 given) I can see the line that it has a problem with, and I see that it is trying to pass 2 arguments. What does it take to change that to work with the new version of Zope? Or is there something else I am missing? Alex Kelly _______________________________________________ Zope-Dev maillist - Zope-Dev@zope.org http://lists.zope.org/mailman/listinfo/zope-dev ** No cross posts or HTML encoding! ** (Related lists - http://lists.zope.org/mailman/listinfo/zope-announce http://lists.zope.org/mailman/listinfo/zope )