Hi, I am using Zope 2.3.0 with ZPatterns 0.4.3b2 and LoginManager 0.8.8b1. When I try to use LoginManager (following the tutorial about LoginManager and SQL), here is the error I get in the browser: Type: TypeError Value: not enough arguments; expected 3, got 2 Traceback (innermost last): File /usr/local/Zope-2.3.0-src/lib/python/ZPublisher/Publish.py, line 222, in publish_module File /usr/local/Zope-2.3.0-src/lib/python/ZPublisher/Publish.py, line 187, in publish File /usr/local/Zope-2.3.0-src/lib/python/Zope/__init__.py, line 221, in zpublisher_exception_hook (Object: Traversable) File /usr/local/Zope-2.3.0-src/lib/python/ZPublisher/Publish.py, line 162, in publish File /usr/local/Zope-2.3.0-src/lib/python/ZPublisher/BaseRequest.py, line 444, in traverse File /usr/local/zope/lib/python/Products/LoginManager/LoginManager.py, line 237, in validate (Object: ProviderContainer) File /usr/local/zope/lib/python/Products/LoginManager/LoginMethods.py, line 149, in findLogin (Object: PlugInBase) File /usr/local/Zope-2.3.0-src/lib/python/Shared/DC/Scripts/Bindings.py, line 324, in __call__ (Object: authenticate) File /usr/local/Zope-2.3.0-src/lib/python/Shared/DC/Scripts/Bindings.py, line 353, in _bindAndExec (Object: authenticate) File /usr/local/Zope-2.3.0-src/lib/python/Products/PythonScripts/PythonScript.py, line 330, in _exec (Object: authenticate) (Info: ... cut ...) TypeError: (see above) I don't know a lot about Zope/Python (I work on it since 2 weeks) so I don't know if this is an install error, a development error (I mean, did I do something wrong when using LoginManager, surely!!), or an error in LoginManager; is this a known error? The error seams to be in LoginMethods.py:149 as it calls user.authenticate() with two parameters where LoginUser's authenticate() takes 3 parameters; but, once again, I might be missing something as I am a beginner... Thanks -- Bertrand Croq - VIRTUAL NET (http://www.virtual-net.fr) 80, avenue des Buttes de Coesmes - 35700 RENNES tel: +33 2 23 21 06 30 - fax: +33 2 99 38 16 85