OK. So I decided to compile it from source. now I get the following error at startup: 2002-08-01T14:03:33 PANIC(300) z2 Startup exception Traceback (innermost last): File /opt/Zope-2.5.1-src/z2.py, line 558, in ? (Object: ZLogger) File /opt/Zope-2.5.1-src/ZServer/HTTPServer.py, line 320, in __init__ File /opt/Zope-2.5.1-src/ZServer/medusa/http_server.py, line 570, in __init__ File /opt/Zope-2.5.1-src/ZServer/medusa/asyncore.py, line 306, in bind error: (98, 'Address already in use') Anybody seen this one before/know a workaround? Thanks ---------- Forwarded Message ---------- Subject: Re: [Zope] Login help Date: Thu, 1 Aug 2002 15:17:06 +0200 From: "Jaroslav Lukesh" <lukesh@k-net.cz> To: "Lawrence Strydom" <laurie@midafrica.com>, <zope@zope.org> Try emmergency user, see Zope book. Regards JL. ---------- OdesÃlatel: Lawrence Strydom <laurie@midafrica.com> combination printed at startup. I have examined the inituser file and can see the username, but the password is encrypted. So I used zpasswd.py to change the inituser password, but for some reason I can still not log in. Authentication failed...would you like to try again..blahblah. I have tried this several times with diferrent username password cobinations(real simple ones) so no fingertrouble. After using zpasswd.py I verify that it actually did change the inituser wich it has, but no entry allowed. -------------------------------------------------------