Lee Harr wrote:
If I define a function inside a PythonScript, can I get that function by name somehow using getattr() or some other way?
As in...
#PythonScript
def abc(): pass
abc = getattr(======, 'abc')
In Python, a 'def' statement binds the newly created function to a name in the current namespace. Your definition acts a little bit like the (totally imaginary) code:
abc = make_function('abc', (), 'pass')
...so 'abc' already exists, there's no need to "get" it.
Example:
def abc(x): return x + 1
y = abc(1)
Sorry, that was a typo. Should have been: f = getattr(======, 'abc') as in: # PythonScript # parameters: # whichFunction='abc' def abc(): return 'this is abc' def cba(): return 'this is bca' f = getattr(======, whichFunction) return f() # end If I do not know which function I want to run until runtime, then I cannot use the function handle, I need to "get" the function by name. Now, I have worked around this problem by defining abc and bac as PythonScripts in the same folder as the original one, then I can use: f = getattr(container, whichFunction) but that is a bit of a hassle if I have a few very simple functions and just want to choose one by name. hmm... now that I think about it, I could also say: funcs = {'abc': abc, 'cba': cba} f = funcs[whichFunction] but it seems like there is probably a very simple handle for the current PythonScript namespace, and I just dont know what it is. Thanks for your help. _________________________________________________________________ Protect your PC - get McAfee.com VirusScan Online http://clinic.mcafee.com/clinic/ibuy/campaign.asp?cid=3963