i dont know for shure but does this work?: index_html = DTMLFile('dtml/manage_myclass.dtml', globals()) it should mean: index_html = DTMLFile('dtml/manage_myclass', globals()) there is no need for the dtml extension the image stuff is right but, remember that the path is relative to the modules home class MyClass(self): this means that you inherit from self ?! from OFS import Folder class MyClass(Folder.Folder): try this - i think that you have to inherit from some zope object and add this object via the zmi or via python good luck the ----- Original Message ----- From: "Jean-François Ménard" <menard.jean-francois@hydro.qc.ca> To: <zope@zope.org> Sent: Tuesday, May 29, 2001 6:45 PM Subject: [Zope] ImageFile in python class
Thanks Marc for your response!
But... There MUST be a better way to publish an image in a python class?
Here is what I would like to do:
class MyClass(self): """ Class example """
image = ImageFile('www/image.gif', globals()) index_html = DTMLFile('dtml/manage_myclass.dtml', globals())
def __init__(self, id, title): """ Initialization of my class """ ...
How can I use the "image" property in my "index_html" dtml file???
I tried:
<dtml-var image> give me a broken image.
Then:
<img src="<dtml-var absolute_url>/image>
Broken image again...
I looked at the code in OFS/misc_ , with no luck...
Any help would be VERY appreciated... I'm stuck on this problem for _too_ long now... : /
Thanks!
J-F
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