RE: [Zope] external methods

After some digging, I found that the problem lies in the expression 'self.l'

'self.' gives access to the object hierarchy, not the variables namespace.

So, I solved my problem by writing 'self.REQUEST['l']' instead of 'self.l'

Also, I think that this should be clearly documented. Apparently, the only way to acess variables namespaces in external methods is through self.REQUEST This confuses a 'normal' python user whose variable namespace is usually accessed through self.

I believe that you can just ask for it in your function signature: def my_method(self,l): return l + ' is cool!' --Paul