26 Feb
2002
26 Feb
'02
4:02 p.m.
How? Em Seg 25 Fev 2002 13:52, Frank Tegtmeyer escreveu:
Sidnei da Silva <sidnei@x3ng.com.br> writes:
seen = {} unique = [] for r in result: if not seen.has_key(r.data_record_id_): seen[r.data_record_id_] = r.data_record_id_ unique.append(r)
return unique
It works OK. Thanx everyone.
You may reduce this to one dictionary :)
Regards, Frank
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