18 Oct
2002
18 Oct
'02
1:35 p.m.
Ick, no lambda needed: items = context.objectItems() items.sort() for id, object in items: print id, object return printed sort is *much* faster when you don't use a comparison function as well (though sometimes you do need them). -Casey On Fri, 18 Oct 2002 10:20:27 +0200 Jerome Alet <alet@librelogiciel.com> wrote:
On Fri, Oct 18, 2002 at 10:15:10AM +0200, Andreas Tille wrote:
Hello,
I just want to build a sorted list of
list = context.objectValues('ExtFile') for file in list: print file.id, file.title return printed
<UNTESTED> list.sort(lambda x,y : cmp(y.getId(), x.getId())) </UNTESTED>
hth
Jerome Alet