Hi Thomas, I do this using an external python method: def LoadFile(filename): try: filein = open(filename, 'r') except IOError: return [] else: result = filein.readlines() filein.close() return result Then from DTML, you get it line-by-line: <dtml-in "LoadFile(filename='/var/zope/var/test.file')"> <dtml-call "REQUEST.set('entry',_['sequence-item'])"> ... at this point, you have a dtml-var called "entry", one for each line of your file </dtml-in> NOTE: the above is a stripped-down, untested version of what I have, so it may not work exactly as is, (though I think it does -- yes, I'm naively optimistic..) Also, if you are reading the line in from the external method, it might be easier to parse the line there. The list that is returned could be a list-of-lists, then the above "entry" dtml-var would be a single list, and you can access the elements of the list from dtml using entry[0], etc. don't know exact syntax for this. Also, its kind of nice for running external programs from an external method: def runit(p1,p2): result = os.popen( "/usr/local/farm9/bin/someprogram %s %s" % (p1,p2) ).readlines() return result Then you can get the results line-by-line exactly the same way as you do from reading the file. Regards, JJ "Thomas Mühlens" wrote:
I stored a whole bunch of parameters in a textfile object (text/plain format) called params. How can I read it into a string variable line by line, that is,
read line1 - parse line1 read line2 - parse line2 ... etc
Is it memory efficient to do this with some <!-- <dtml-in> </dtml-in> --> syntax?
cheers, tom
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