Hi, On Thu, 2004-11-04 at 09:57, Garito wrote:
Garito wrote:
Hi will these be possible?
<tal:b tal:define='dictionary python: {"value1": ["one", "two", "three"], "value2": "two", "value3": "three"}'> <tal:b tal:replace='python: dictionary["value1"][5] | "Value not available"' /> </tal:b>
Obviously these is an incorrect tal expression (the replace one) but there are any way to create an expression like these and correct?
Thank you!!!
Now I have a correct expression (thanks to Chema Cortés from spanish zope list). This is the expression:
(len(dictionary['value1'])>6 and dictionary['value1'][5]) or 'Value not available'
Just for the records: (dictionary.get('value',[])[5:]+['Value not available'])[0] is the functional programming approach to this problem. Regards Tino