Re: [Zope] external methods

On Fri, 26 Mar 1999, Service Informatique CHSR wrote:

'self.' gives access to the object hierarchy, not the variables namespace.

So, I solved my problem by writing 'self.REQUEST['l']' instead of 'self.l'

Also, I think that this should be clearly documented. Apparently, the only way to acess variables namespaces

Jephte In your external method l is a local variable. You can access it by simply referencing it. something like def spammethod: l=[] for i in [1,2]: l.append(i) return l Pavlos