Pawel Lewicki wrote:
Hallo, I have 2 forms in my CMF site (but I suppose that is not a problem). Both of them have <input name="image_file" type="file" > field. I try to get the file name to add a file(image) with proper id. When I access str(REQUEST.image_file) in my python script one time I get the full path to the file and the second time: <ZPublisher.HTTPRequest.FileUpload instance at 020CF314> The first one is better for me for explained reason but the files seem not to be uploading. So it is probably just a name not a file. The first question is where is the difference? It's probably in the code but I can't find it. I don't know much about HTTP protocol but the first thing to check was the type of forms - both are "POST" type. And the second - how to extract the name of the file and have it uploaded in the same time?
Pawel Lewicki
your_target_to_add_image.manage_addImage('',image_file) should do the trick, it causes zope to construct the id itself (see OFS/Image.py, the method is called CookId) from the filename.
Additionally, image_file.filename gives you the filename of the uploaded file, but you might have to strip off the leading path.
HTH, oliver
I have to use the second solution as context.invokeFactory(id='image_name', type_name='Image', file=request.image_file) requires id to be given. But image_file.filename works great. Thanx Pawel