Hello Demont! a) If I understand you correctly, you want to upload a file from the client's file system to the server's ZODB as a new "file" object. Use: <dtml-call "folderobjectofyourchoice.manage_addFile('id_of_your_choice', file)"> (Make sure you had enctype="multipart/form-data" set in your form tag) This call will set the new file object's title to the filename by default. You have said that you want to set the _title_, but didn't mention the new object's id. If you specify keyword arguments, you can set everything by hand: <dtml-call "folderofyourchoice.manage_addFile(title='title of your choice', file=file, id='the_order_of_keyword_arguments_is_irrelevant')"> b) Please do not post on both "zope@zope.org" AND "zope-dev@zope.org" (see generated footer in mail) c) zope-dev is meant to be a mailing list for the development OF Zope, not WITH Zope. zope@zope.org would have been the appropriate place for posting. See http://www.zope.org/Resources/MailingLists d) Your question was definitely a FAQ. The Mailing List Archives are a very good place to start looking for an answer. Actually, I got more answers from there than from anyone personally! You can search them at NIP: http://zope.nipltd.com/public/lists.html Hope this helps, Danny On Wednesday 28 November 2001 21:29, Demont Maarten wrote:
Hey
I want to insert a file from my "normal" file system into the ZODB database. I have collected the path from a form-field "file". The file that needs inserting must be placed in a certain folder inside Zope, and gets a title that I base upon a certain number.
How can I - using DTML - insert this file?
Can anyone supply me (fast, this is quite urgent...) with a few lines of code explaining this?
Thanx!!!!!
Maarten Demont maarten.demont@cronos.be Zope-Newbie
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