Re: [Zope] An accessrule in python script

3 Oct 2001

      Many thanks Danny,

My Zope server is behind an Apache server that makes rewrite to
www.site1.com:8080
This was my (stupid) mistake. Should have been obvious !
It works now with :

machine = _.string.lower(_.string.split(context.REQUEST.HTTP_HOST, ':')[0])
# and so on...

The complete accessrule script is :
===============
machine = _.string.lower(_.string.split(context.REQUEST.HTTP_HOST, ':')[0])
servermap = {
  'www.site1.com': 'folder_site1',
  'www.site2.com': 'folder_site2'
  }
if servermap.has_key(machine):
    context.REQUEST['TraversalRequestNameStack'].append(servermap[machine])
return
==============
With the namespace bound to '_'

Cheers

--Gilles

----- Original Message -----
From: "Danny William Adair" <danny@adair.net>
To: "Gilles Lenfant" <glenfant@bigfoot.com>; <zope@zope.org>
Sent: Wednesday, October 03, 2001 12:07 AM
Subject: Re: [Zope] An accessrule in python script
...
Hi Gilles,
if your current script looks exactly like this:
----------------------------------------------------------------
from string import lower
request = container.REQUEST
machine = lower(request.HTTP_HOST)
servermap = {
  'www.site1.com': 'site1',
  'www.site2.com': 'site2'
  }
if servermap.has_key(machine):
    request['TraversalRequestNameStack'].append(servermap[machine])
----------------------------------------------------------------
and fails, then something odd is going on. I don't see any mistake.
Hold on...
If you're running Zope on a port other than 80,
machine = lower(split(request.HTTP_HOST, ':')[0])
should do the trick (to get rid of the :port)
I recognized you had used that in your DTML.
Did you "re"-set the access rule?