I must be stupid, but are you sure that your FTP port in remote machine is 21? Or is it 8021 as in a default Zope install? S Babu http://vsbabu.org/ On Tue, Nov 12, 2002 at 05:05:21PM +0100 or thereabouts, Elena Schulz wrote:
Hi,
I want to connect my local Zope (win98, Zope 2.5.1) to a remote Zope-Server only by ftp-access. The following external method from zopelabs seems to connect somehow but doesn work (no files are sent):
1. How can I log the info from the remote Server to see where the problem is? 2. Is "_ftp.set_pasv(1)" ok to enable passive mode for operating from behind a firewall?
Has anybody positive experience with this or other methods of ftp-connection between 2 Zope-server? Thanks for any help and replies,
Elena
The external-script:
""" sendfiles from ZOPE to another machine ftp by runyaga @ zopelabs """
import ftplib from string import split, lower from StringIO import StringIO
host='localhost' login='runyaga' password='^%$^@5@#$S' port=21
def ftp(obj, host=host, login=login, password=password, port=port): _ftp = ftplib.FTP() _ftp.set_pasv(1) #for firewall < ######## 2 ############ #_ftp.connect(host, port) _ftp.connect(host) # with default port _ftp.login(login, password)
if lower(obj.meta_type)=='file': binary=1 if obj.content_type[:4]=='text': binary=0 ftp_file(_ftp, obj, binary)
if lower(obj.meta_type)=='image': ftp_file(_ftp, obj, 1)
_ftp.quit()
def ftp_file(ftpCon, fileObj, binary): if binary: ftpCon.storbinary("STOR " + fileObj.getId(), StringIO(fileObj.data), 1024) else: f = StringIO() f.readlines(split(fileObj.data, '\n')) f.seek(0) ftpCon.storlines("STOR " + fileObj.getId(), f)
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