----- Original Message ----- From: "Eric Balasbas" <ebalasba@bway.net> To: "Tim Hicks" <tim@sitefusion.co.uk> Cc: <zope@zope.org> Sent: Wednesday, June 13, 2001 4:33 PM Subject: Re: [Zope] How to make a script return rendered dtml
I'm not sure if this is the best way to do it, but if you want to render a DTML method or DTML document inside a Python script, use the syntax:
someDTMLMethod(_.None, _)
I tried this: print context(_.None, _) and got this error: Error Type: NameError Error Value: _ So I tried context.id(_.None,_) and got the same. So I tried 'print context(None,_)', with the same error resulting. Finally, I have tried: print context(None,) and got Error Type: KeyError Error Value: standard_html_header This last error at least seems like it's on the right track as it is parsing through the text of the file. What's going wrong, any idea? thanks tim
Eric Balasbas Senior Developer eric@virtosi.com
http://www.virtosi.com/ Virtosi Ltd. Design -- Branding -- Zope
On Wed, 13 Jun 2001, Tim Hicks wrote:
I have a ZClass (testclass) which subclasses DTMLDocument, and within this zclass, I have a script (python) called index_html. Obviously, this script is called each time an instance of testclass is requested. Based on the presence of a query string, I want to either return the document_src (although with a few modifications), or simply return the rendered instance... by this, I mean have all the dtml tags that are in the instance evaluated. So, my question is, how do I make Zope evaluate the dtml tags?
Here is what I have so far in my script:
------------ if context.REQUEST.QUERY_STRING == 'editor': print context.raw else: print context
return printed ------------
The 'else' statement simply gives me things like,
<dtml-var standard_html_header>
I also tried 'else: render(context)', which was simply a guess on my part, but I get a Zope error as follows:
Error Type: AttributeError Error Value: validate
Can anyone enlighten me?
Cheers
tim
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