pass along username and password like this:: ZPublisher.Zope(url, u="username:password", d=1) jens On Sunday, October 7, 2001, at 01:07 , Christoph Wierling wrote:
I try to debug my Zope (Zope-2.4.1) application by the use of the following script ('debug.py'):
import Zope, ZPublisher from AccessControl.SecurityManagement import newSecurityManager
def zope (url): app = Zope.app() admin = app.acl_users.getUser('admin') newSecurityManager(None, admin)
ZPublisher.Zope(url, d=1)
Then I start up python and import this module. By calling >>> debug.zope('/') I can debug without any problems, but by calling >>> debug.zope('/manage') I get the following traceback during debugging:
Traceback (innermost last): File /src/Zope-2.4.1-src/lib/python/ZPublisher/Test.py, line 263, in publish_module File /src/Zope-2.4.1-src/lib/python/ZPublisher/Publish.py, line 187, in publish File /src/Zope-2.4.1-src/lib/python/ZPublisher/Publish.py, line 162, in publish File /src/Zope-2.4.1-src/lib/python/ZPublisher/BaseRequest.py, line 463, in traverse File /src/Zope-2.4.1-src/lib/python/ZPublisher/HTTPResponse.py, line 581, in unauthorized Unauthorized: (see above)
In my Zope application 'admin' does have the right to access '/manage', so in principle it should work.
Does anybody know, way I run into an unauthorization error?
Christoph
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