Hi!
For me, it's easier in pure Python, but I upload the data in the filesystem (not in ZODB) Anyway, you can get the uploaded content (not the file path) with the "read" method.
No, I tried that. The read()-Method stops the first time it encounters chr(0), so when I try to upload my file like TargetFolder.manage_addFile(NewDocumentName,open(DocumentPath,'r').read()) it will be only 6 bytes big. Funny thing is, if I upload it from DTML, everything works fine and I get the full 19K. I copy the two pages again, that do the upload, because I have some questions about them. Obviously, DoUpload receives a parameter "DateiName" which is n o t a string, because it has an attribute ".filename". So my general problem can be reduced to 2 questions: 1. what is the name of the class "DateiName" is an instance of? 2. How can I convert a string that denotes a path into an instance of this class? By the way: is there a run-time-type-identification in python (some function that takes an object as arg and returns the name of its class)? DTML-Document "index_html": <html> <form action="DoUpload" enctype="multipart/form-data" method="post"> <input type="file" name="DateiName"> <input type=submit value="upload"></td></tr> </form> </html> DTML-Method "DoUpload": <html> <dtml-let fname="_.string.split(DateiName.filename,'\\')[-1]"> <dtml-with upload> <dtml-if "_.has_key(fname)"> <dtml-call "_[fname].manage_upload(DateiName)"> <dtml-else> <dtml-call "manage_addFile(fname,DateiName)"> </dtml-if> <form action="upload/<dtml-var fname>" method="post"> <input type="submit" value="view"> </form> </dtml-with> </dtml-let> </html> _________________________________________________________________ Downloaden Sie MSN Explorer kostenlos unter http://explorer.msn.de/intl.asp