Am 08.02.2002, 12:18 Uhr schrieb Peter Walerowski <peter.walerowski@berlin.de>:
it would be nice to have the possibilty to iterate through two or more sequence items in one pass, wouldn't it?
Hai Peter! That's easily possible if you manipulate your list to reflect your data processing requirements. You want to have to items in one iteration so IMHO the pythonic solution is not to skip every other item but to construct a list of tuples each containing two items. Assuming your list looks like this: m=["a","b","c","d","e","f"] you can do this by: newlist=map(lambda x:(m[x],m[x+1]), range(0,len(m)-2,2)) which results in: [('a', 'b'), ('c', 'd'), ('e', 'f')] You'll have to make sure that your original list has an even number of items. Happy zoping! Jo. -- Internetmanufaktur Jo Meder ---------------------- Berlin, Germany http://www.meder.de/ ------------------- fon: ++49-30-417 17 63 33 Kollwitzstr. 75 ------------------------ fax: ++49-30-417 17 63 45 10435 Berlin --------------------------- mob: ++49-170- 2 98 89 97 Public GnuPG-Key ---------- http://www.meder.de/keys/jo-pubkey.txt