When I run ./start to get zserver/pcgi up and running, I get an error telling me Zope-2.1.6-src/var/Z2.pid permission denied.....yet when I look in that directory, Z2.pid is not even there...hmm. Any ideas why it looks for a directory that doesn't exist? This is really the only thing holding the ./start program back, from what I can tell. I even tried making an empty Z2.pid file and even put permissions 777 on it (not a good idea I know, but just for the ./start)...and I still get the same "permission denied" error....hmm. (and I am running as root, using sudo). Here is error is detail: File "/home/jessi/Zope-2.1.6-src/z2.py", line 586, in ? IOError: [Errno 13] Permission denied: '/home/jessi/Zope-2.1.6-src/var/Z2.pid' Thanks in Advance, Jessica
jessica lee tishmack wrote:
When I run ./start to get zserver/pcgi up and running, I get an error telling me Zope-2.1.6-src/var/Z2.pid permission denied.....yet when I look in that directory, Z2.pid is not even there...hmm. Any ideas why it looks for a directory that doesn't exist? This is really the only thing holding the ./start program back, from what I can tell.
z2.pid is the file that contains the process ID of zope, so that the stop script knows what to stop. ./start does not have write access to the directory var. You are either: a. starting it as a user that cannot access zope/var: b. starting it as root, and not giving nobody permission to write to zope/var. -- ethan mindlace fremen mindlace@imeme.net zope -&- imap email -&- mailing list weave your web with the web at http://imeme.net
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