Sorry Alex, This was stuff I did so long ago I can't remember what I did, nor who I stole it from. getMimeType is an external method that goes like this: import string def getMimeType(self,file): __allow_access_to_unprotected_subobjects__=1 contentHeader=file.headers.headers[1] mimeType=string.split(contentHeader, ': ')[1] return mimeType The site is a private corporate internet, so you can't go there anyway. -- HTH -- Loren

-----Original Message----- From: Alex [mailto:alex@quad.com.ar] Sent: Friday, June 01, 2001 09:54 To: Loren Stafford Subject: Re: [Zope] Content-Type missing for uploads?

thanks for your reply, but I'm afraid <dtml-boundary> is something to be used within <dtml-mime> which is part of the <dtml-sendmail> tag. well, I tried it anyway, and I get an error on 'getMimeType' being invalid.

anyway, what is the url of that site you mentioned?

Thanks!

alex

----- Original Message ----- From: "Loren Stafford" <lstafford@morphics.com> To: "Alex" <alex@quad.com.ar>; <zope@zope.org> Sent: Thursday, May 31, 2001 11:01 PM Subject: RE: [Zope] Content-Type missing for uploads?

...

Here's some code I found on my site:

<dtml-boundary type_expr="getMimeType(CVfile)" name_expr="uploadFileName(CVfile.filename)" disposition=attachment encode=base64>

getMimeType(UploadFileObject) seems to be the trick.

-- Loren

...

-----Original Message----- From: zope-admin@zope.org [mailto:zope-admin@zope.org]On Behalf Of Alex Sent: Thursday, May 31, 2001 17:43 To: zope@zope.org Subject: [Zope] Content-Type missing for uploads?

How can I get the Content-Type of a file that has been uploaded with a form?

example:

<form method="post" enctype="multipart/form-data"> <input type="file" name="myfile"> <input type="submit"> </form>

when you upload a file with this form, the browser sends the Content-Type of "myfile" , the question is: How can I get that Content-Type information from zope?

By the way, it's not REQUEST.CONTENT_TYPE, as this is set to multipart/form-data.

any ideas?? Thanks

Alex