I used this code in my "logoutForm" to logout user in my old setup (LoginManager-0_8_7a1, ZPatterns-0-4-2a1 and Zope 2.2.1): <dtml-call "AUTHENTICATED_USER.logout()">

(I assume this code is correct, as it is included in default logoutForm in LoginManager.)

It doesn't work when using LoginManager-0-8-8b1 + ZPatterns-0-4-3b2 + Zope 2.2.4.

I forgot to write HOW it fails: Error Type: AttributeError Error Value: logoutUser Traceback (innermost last): File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/ZPublisher/Publish.py, line 222, in publish_module File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/ZPublisher/Publish.py, line 187, in publish File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/Zope/__init__.py, line 221, in zpublisher_exception_hook (Object: ProviderContainer) File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/ZPublisher/Publish.py, line 171, in publish File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/ZPublisher/mapply.py, line 160, in mapply (Object: logoutForm) File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/ZPublisher/Publish.py, line 112, in call_object (Object: logoutForm) File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/OFS/DTMLDocument.py, line 177, in __call__ (Object: logoutForm) File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/DocumentTemplate/DT_String.py, line 528, in __call__ (Object: logoutForm) File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/DocumentTemplate/DT_Util.py, line 337, in eval (Object: AUTHENTICATED_USER.logout()) (Info: AUTHENTICATED_USER) File <string>, line 0, in ? File /usr/local/digicool/Zope-2.2.4-linux2-x86/lib/python/Products/LoginManager/UserSources.py, line 107, in logout (Object: BetterLocalRolesMixin) AttributeError: (see above)

I've found a work-around: <dtml-call "acl_users.logoutUser(AUTHENTICATED_USER.getId())"> It logouts user as expected.

But, can anybody tell me, why the former one doesn't work as it should ?

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