RE: ZopeTime() and string.split/string.join
Nevermind. Sorry... The answer is to replace <dtml-let tmp_time="ZopeTime()"> with <dtml-let tmp_time="_.str(ZopeTime())"> This changes the object value into a string. Ugh. -----Original Message----- From: Chris McDonough Sent: Monday, September 20, 1999 9:06 PM To: 'zope@zope.org' Subject: ZopeTime() and string.split/string.join When I call this DTML method (in a container titled "News Items"): <!--#var standard_html_header--> <dtml-let tmp_time="title"> <dtml-var "_.string.join(_.string.split(tmp_time,' '),'_')"> </dtml-let> <!--#var standard_html_footer--> I am returned the header, a line that says "News_Items", and the footer. However, when I call this DTML method: <!--#var standard_html_header--> <dtml-let tmp_time="ZopeTime()"> <dtml-var "_.string.join(_.string.split(tmp_time,' '),'_')"> </dtml-let> <!--#var standard_html_footer--> I get the following traceback: Error Type: TypeError Error Value: argument 1: expected read-only character buffer, instance found Traceback (innermost last): File /usr/local/Zope-2.0.0/lib/python/ZPublisher/Publish.py, line 214, in publish_module File /usr/local/Zope-2.0.0/lib/python/ZPublisher/Publish.py, line 179, in publish File /usr/local/Zope-2.0.0/lib/python/Zope/__init__.py, line 201, in zpublisher_exception_hook (Object: ElementWithAttributes) File /usr/local/Zope-2.0.0/lib/python/ZPublisher/Publish.py, line 165, in publish File /usr/local/Zope-2.0.0/lib/python/ZPublisher/mapply.py, line 160, in mapply (Object: test) File /usr/local/Zope-2.0.0/lib/python/ZPublisher/Publish.py, line 102, in call_object (Object: test) File /usr/local/Zope-2.0.0/lib/python/OFS/DTMLMethod.py, line 145, in __call__ (Object: test) File /downloads/Zope-2.0.0-src/lib/python/DocumentTemplate/DT_String.py, line 502, in __call__ (Object: test) File /downloads/Zope-2.0.0-src/lib/python/DocumentTemplate/DT_Let.py, line 145, in render (Object: tmp_time="ZopeTime()") File /downloads/Zope-2.0.0-src/lib/python/DocumentTemplate/DT_Util.py, line 321, in eval (Object: _.string.join(_.string.split(tmp_time,' '),'_')) File <string>, line 0, in ? TypeError: (see above) Why is this?
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Chris McDonough