Hi all, I have just set up a folder which is designed to contain details of all our users. I've set up a ZClass for these users. The problem I am having is the transferance from our old system to our new one. I have a file containing all the email addresses of the old users (which is all I need initially), one per line, and want to write a script that steps through this file and processes the users into the Zope interface. The problem I am having is that I am finding it impossible to actually open the file within zope so you can actually use it. I've tried scripting with filein = open(file) But that never actually worked. I've tried it in Zope methods with "<dtml-in "_.getitem(file).split('\n')"> But that assumes it is a string (I admit, it was wishful thinking when I tried that). Does anyone know of a way to read a text file, contained in zope, and step through it? I've looked in the archives, and not found a way. Thanks! Di
On Friday 05 July 2002 06:58, Dianne Van Dulken wrote:
Hi all,
I have just set up a folder which is designed to contain details of all our users. I've set up a ZClass for these users.
The problem I am having is the transferance from our old system to our new one. I have a file containing all the email addresses of the old users (which is all I need initially), one per line, and want to write a script that steps through this file and processes the users into the Zope interface.
The problem I am having is that I am finding it impossible to actually open the file within zope so you can actually use it. I've tried scripting with
filein = open(file)
Write an external method or load the file into the zope database via the management screens.
I've tried it in Zope methods with
"<dtml-in "_.getitem(file).split('\n')">
But that assumes it is a string (I admit, it was wishful thinking when I tried that).
Does anyone know of a way to read a text file, contained in zope, and step through it? I've looked in the archives, and not found a way.
save that file as DTML-Document, not as file. then you can achieve what you intent with <dtml-in "nameOfYourDataObject().split('\n')"> mfg AND -- I doubt, therefore I might be.
I just did this with a file: my_file = split(file.data,'\r\n') the .data returns the contents of the file hth Laurie -----Original Message----- From: zope-admin@zope.org [mailto:zope-admin@zope.org]On Behalf Of Andreas Lauser Sent: Friday, July 05, 2002 5:32 AM To: Dianne Van Dulken Cc: zope@zope.org Subject: Re: [Zope] Accessing Files within Zope? On Friday 05 July 2002 06:58, Dianne Van Dulken wrote:
Hi all,
I have just set up a folder which is designed to contain details of all our users. I've set up a ZClass for these users.
The problem I am having is the transferance from our old system to our new one. I have a file containing all the email addresses of the old users (which is all I need initially), one per line, and want to write a script that steps through this file and processes the users into the Zope interface.
The problem I am having is that I am finding it impossible to actually open the file within zope so you can actually use it. I've tried scripting with
filein = open(file)
Write an external method or load the file into the zope database via the management screens.
I've tried it in Zope methods with
"<dtml-in "_.getitem(file).split('\n')">
But that assumes it is a string (I admit, it was wishful thinking when I tried that).
Does anyone know of a way to read a text file, contained in zope, and step through it? I've looked in the archives, and not found a way.
save that file as DTML-Document, not as file. then you can achieve what you intent with <dtml-in "nameOfYourDataObject().split('\n')"> mfg AND -- I doubt, therefore I might be. _______________________________________________ Zope maillist - Zope@zope.org http://lists.zope.org/mailman/listinfo/zope ** No cross posts or HTML encoding! ** (Related lists - http://lists.zope.org/mailman/listinfo/zope-announce http://lists.zope.org/mailman/listinfo/zope-dev )
On Friday 05 July 2002 11:48 am, Laurie Nason wrote:
I just did this with a file: my_file = split(file.data,'\r\n') the .data returns the contents of the file
hth
Laurie
BTW file.data is only the first chunk of the file's data (currently 64Kb in size). So the above will truncate a file to 64K. To get the entire contents of a file object, use: data = str(file) -Casey
participants (4)
-
Andreas Lauser -
Casey Duncan -
Dianne Van Dulken -
Laurie Nason