sorry - there was a mistake in the dtml-in expression in my earlier query. here it is corrected: ---- hi folks, suppose i have some images in a folder, named image1, image2 and image3, and the following DTML method: <dtml-in expr="['image1', 'image2', 'image3']"> <p><dtml-var expr="_.getitem(_['sequence-item'])"></p> </dtml-in> this yields something of the form: <p><img src="http://localhost:8080/test/image1" alt="image one" height="32" width="90" border="0" /></p> <p><img src="http://localhost:8080/test/image2" alt="image two" height="32" width="90" border="0" /></p> <p><img src="http://localhost:8080/test/image3" alt="image three" height="32" width="90" border="0" /></p> (incidentally, this is the case whether or not i pass 'true' to the 'render' argument of getitem()). first question (the answer to which is probably obvious, but i'm new to zope): - why does the following not yield the same result? <dtml-in expr="['image1', 'image2', 'image3']"> <p><dtml-var sequence-item></p> </dtml-in> (yields: <p>image1</p>\n<p>image2</p>\n<p>image3</p>) second question: - i want to pass an extra argument to the image object. the following code works: <dtml-in expr="['image1', 'image2', 'image3']"> <p><dtml-var expr="_.getitem(_['sequence-item']).tag(name=_['sequence- item'])"></p> </dtml-in> yielding: <p><img src="http://localhost:8080/test/image1" alt="image one" height="32" width="90" border="0" name="image1" /></p> <p><img src="http://localhost:8080/test/image2" alt="image two" height="32" width="90" border="0" name="image2" /></p> <p><img src="http://localhost:8080/test/image3" alt="image three" height="32" width="90" border="0" name="image3" /></p> but this is based on knowledge that Image.__str__() calls tag(), which i do not want to rely upon. instead i want to call the object in the same way as it is called when i use a simple tag such as '<dtml-var image1>'. how do i achieve this? (using expr="_.getitem(_['sequence-item'])(name=_['sequence-item'])", i.e., dropping the '.tag', yields an AttributeError of value __call__). thanks in advance, hamish -- Get your firstname@lastname email for FREE at http://Nameplanet.com/?su