Hello zopists, I create a small application. User enters file via web interface, and this is parsed and pushed into SQL. the input form is DTML method like this ==== DTML method: send_file == I use [] instead of <> [dtml-var standard_html_header] ... [form action="receive_file" method="post" enctype="multipart/form-data"] ... [input type="File" name="file" value=""] ... [input type="submit" value=" Send File "] ... [/form] [dtml-var standard_html_footer] ====== end of file ===== The receive_file is external python method ===== receive_file, function name= rcv_file from string import strip import pg def rcv_file(self, REQUEST): ... fileobj = REQUEST.form['file'] filelist = fileobj.readlines() fileobj.close for line in filelist: (* parse line and push it into SQL server *) ... ====== end of file ==== Is there any way how to get a name of uploaded file. I mean another than let user type the name in another field. I was looking in REQUEST object and nothing about the filename found there. I allso read Zope Book, digging in documentation arround, but with no success. -- Radek Hnilica <Radek_Hnilica at LinuxFan dot COM>