Hi, I am using an external method to load an Image from the harddrive. The external method is as follows: from email.MIMEImage import MIMEImage ##parameters=filename def getDocument(filename): fname = '/mnt/'+filename; input = open(fname,'r') content = MIMEImage( input.read( ) ) input.close( ) return content When I try to display the content in the webpage what I actually got is all raw data of the file rather the image. So how can I convert the raw data to be dispalyed as image in the webpage. I am using ZPT to display the web page (image). If its dtml I could have used <dtml-mime> tag is there any equivalent to that in ZPT. Any suggestion would be a gr8 help. Ta.
srikanth wrote:
Hi,
I am using an external method to load an Image from the harddrive. The external method is as follows:
from email.MIMEImage import MIMEImage ##parameters=filename def getDocument(filename): fname = '/mnt/'+filename; input = open(fname,'r') content = MIMEImage( input.read( ) ) input.close( ) return content
When I try to display the content in the webpage what I actually got is all raw data of the file rather the image. So how can I convert the raw data to be dispalyed as image in the webpage. I am using ZPT to display the web page (image). If its dtml I could have used <dtml-mime> tag is there any equivalent to that in ZPT.
Any suggestion would be a gr8 help.
It is not clear exactly how you are using the Page Template. Typically the page would have an img tag that calls a python script that calls the External Method. Remember the web browser fetches the image separately after the html has been received - so your img tag might look like this: <img src="getImage?filename=whatever" ...> and your getImage python script would look like this: (type, encoding) = context.getMimeType(context.REQUEST.filename) context.REQUEST.RESPONSE.setHeader('Content-Type', type) context.REQUEST.RESPONSE.setHeader('Content-Disposition', 'inline; return context.getDocumentCall(context.REQUEST.filename) where getDocumentCall is the name of your External Method that calls the getDocument External Method and getMimeType is another External Method that looks like this: import mimetypes def getMimeType(filename): return mimetypes.guess_type(filename) and your own external method would look like this:
##parameters=filename def getDocument(filename): fname = '/mnt/'+filename; input = open(fname,'r') content = input.read( ) input.close( ) return content
At the moment you seem to have skipped a step. HTH Cliff
Ta.
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srikanth wrote at 2005-4-5 13:11 -0700:
I am using an external method to load an Image from the harddrive. The external method is as follows:
from email.MIMEImage import MIMEImage ##parameters=filename def getDocument(filename): fname = '/mnt/'+filename; input = open(fname,'r') content = MIMEImage( input.read( ) ) input.close( ) return content
When I try to display the content in the webpage what I actually got is all raw data of the file rather the image. So how can I convert the raw data to be dispalyed as image in the webpage. I am using ZPT to display the web page (image).
Apparently, you do not yet fully understand HTML and ZPT. HTML (and therefore ZPT) is *NOT* intended to present binary data (such as images). I expect you do not understand "MIMEImage" as well. I do not know what it is for but almost surely, it is not for presentation via HTTP...
If its dtml I could have used <dtml-mime> tag is there any equivalent to that in ZPT.
And it would not work. "dtml-mime" is for construction of an "email" message from DTML and not for a webpage presentation. Step back. Read a good book about Web publishing, HTML and HTTP. Learn about how to present binary information in web pages (i.e. via HTTP) -- you will need the "Content-Type" header of HTTP responses. Read about Zope's "REQUEST" and "RESPONSE" objects (in the Zope book or <http://www.dieter.handshake.de/pyprojects/zope/book/chap3.html>) You will *not* need a ZPT (nor DTML) for presentation of binary content. You use then only for textual content. -- Dieter
Am Dienstag, den 05.04.2005, 13:11 -0700 schrieb srikanth:
Hi,
I am using an external method to load an Image from the harddrive. The external method is as follows:
from email.MIMEImage import MIMEImage ##parameters=filename def getDocument(filename): fname = '/mnt/'+filename; input = open(fname,'r') content = MIMEImage( input.read( ) ) input.close( ) return content
When I try to display the content in the webpage what I actually got is all raw data of the file rather the image. So how can I convert the raw data to be dispalyed as image in the webpage. I am using ZPT to display the web page (image). If its dtml I could have used <dtml-mime> tag is there any equivalent to that in ZPT.
This is not a domain for templating languages like DTML or ZPT. Images are read seperately by the client (get a sniffer like shanes tcpwatch or tcpflow and see whats going on there) So your external method has to set the headers. Unfortunalely you open a huge security hole with your solution and by not reading the python documentation carefully ;) fname = '/mnt/'+filename; <--- if I put a filename like "../etc/passwd" I start to have fun. Ah, and image data for web pages are raw. So you dont need mimeimage alltogether. Just open().read() Again, if you want performance, you should use: from ZPublisher.Iterators import filestream_iterator return filestream_iterator(filenameondisk,'rb') Regards Tino
participants (4)
-
Cliff Ford -
Dieter Maurer -
srikanth -
Tino Wildenhain