The ftplib that came with my Zope 2.5.1 win32 is giving an error on socket's sendall method. Is there anything I'm doing wrong, or is it a bug in this particular version or my installation? Thanks. C:\Program Files\Zope>bin\python.exe Python 2.1.3 (#35, Apr 8 2002, 17:47:50) [MSC 32 bit (Intel)] on win32 Type "copyright", "credits" or "license" for more information.

...

...

from ftplib import FTP ftp = FTP('localhost') ftp.login() Traceback (most recent call last): File "<stdin>", line 1, in ? File "C:\Program Files\Zope/bin/lib\ftplib.py", line 317, in login resp = self.sendcmd('USER ' + user) File "C:\Program Files\Zope/bin/lib\ftplib.py", line 228, in sendcmd self.putcmd(cmd) File "C:\Program Files\Zope/bin/lib\ftplib.py", line 163, in putcmd self.putline(line) File "C:\Program Files\Zope/bin/lib\ftplib.py", line 158, in putline self.sock.sendall(line) File "<string>", line 1, in sendall AttributeError: sendall

But it works fine on my Python2.2 on the same machine, in a different dir. PythonWin 2.2.1 (#34, Apr 9 2002, 19:34:33) [MSC 32 bit (Intel)] on win32. Portions Copyright 1994-2001 Mark Hammond (mhammond@skippinet.com.au) - see 'Help/About PythonWin' for further copyright information.

...

...

from ftplib import FTP ftp = FTP('localhost') ftp.login() '230 Anonymous user logged in.' ftp.retrlines('LIST') '226 Transfer complete.'

What's New in Python 2.1.2 (rc1)? ================================= - The socket object gained a new method, 'sendall()'. This method is guaranteed to send all data - this is not guaranteed by the 'send()' method. See also SF patch #474307. The standard library has been updated to use this method where appropriate. My _socket.pyd has the following signature: 36.0 KB (36,927 bytes) Thursday, May 31, 2001, 8:02:06 AM I'm presuming it is the original that comes with Zope 2.5.1